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|[1,a,b],[-a,1,c],[-b,-c,1]|...

|[1,a,b],[-a,1,c],[-b,-c,1]|

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Show that |[-1,b,c],[a,-1,c],[a,b,-1]|=(a+1)(b+1)(c+1)(a/(a+1)+b/(b+1)+c/(c+1)-1)

prove without expanding, |[(a-b),1,a],[b-c,1,b],[c-a,1,c]|=|[a,1,b],[b,1,c],[c,1,a]|

det[[1,a,b-a,1,c-b,-c,1]]=1+a^(2)+b^(2)+c^(2)

The value of |[[1,a,b+c],[1,b,c+a],[1,c,a+b]]| is

Evaluate the following: |[1,a, b c],[1,b, c a],[1,c, a b]|

If D=[[1,a,b],[1,b,c],[1,c,a]] , then [[a,b,c],[b,c,a],[1,1,1]] =

Evaluate [[1,a,b+c],[1,b,c+a],[1,c,a+b]]

Fill in the blanks with appropriate answer from the brackes. [[1,a,b+c],[1,b,c+a],[1,c,a+b]] =_______

Show without expanding at any stage that: [1,a,b+c],[1,b,c+a],[1,c,a+b]|=0

Show that |[1,a ,b+c],[1,b, c+a],[1,c ,a+b]|=0 .