`sin3x + sinx = cos6x + cos4x`

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Integrate : int (sin6x + sin4x) / (cos6x + cos4x) dx .

The general solution of sinx - 3sin2x + sin3x = cosx - 3cos2x + cos3x is :

The general solution of sinx - 3 sin 2x + sin3x = cos x - 3 cos 2x + cos 3x is.

Prove that sin4x = 4sinx cos^3x - 4cosx sin^3x

Prove that : (cos 4x sin 3x - cos 2x sin x)/(sin 4x .sin x + cos 6x .cos x) = tan 2x

sin 3x + sin 2x - sinx = 4sin x cos "" x/2 cos "" (3x)/(2)

(cos 4x sin 3x -cos 2x sin x )/(sin 4x sin x+ cos 6x cos x)= tan 2x

(sin3x-sinx)/(cos2x) =