[" 43.The equation of motion of a projectile is "],[qquad y=12x-(3)/(4)x^(2)]

The equation of motion of a projectile is y = 12 x - (3)/(4) x^2 . The horizontal component of velocity is 3 ms^-1 . What is the range of the projectile ?

The equation of motion of a projectile is y = 12 x - (3)/(4) x^2 . The horizontal component of velocity is 3 ms^-1 . What is the range of the projectile ?

The equation of motion of a projectile is y = 12 x - (3)/(4) x^2 . The horizontal component of velocity is 3 ms^-1 . What is the range of the projectile ?

If the equation of motion of a projectile is y=3x -1/8 x^(2) the range and maximum height are respectively (y and x are in metres)

If the equation of motion of a projectile is y=3x -1/8 x^(2) the range and maximum height are respectively (y and x are in metres)

If the equation of motion of a projectile is y = 3x -1/8 x^(2) , the range and maximum height are respectively (y and x are in metres).

The equation of motion of a projectile is y =ax - bx^2 where a and b are constants of motion. The horizontal range of the projectile is

The equation of a trajectory of a projectile is y=8x-4x^(2) . The maximum height of the projectile is ?