" The truth table of "(sim p)^^q" is "...

" The truth table of "(sim p)^^q" is "

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The truth table of (~p) ^^ (~q) is

The truth table of (~p) ^^ q is

The incorrect statement is p rarr q is logically equivalent to -p vv q. If the truth-values of p,qr are T,F,T respectively,then the truth value of (p vv q)^^(q vv r) is T .sim(p vv q vv r)-=sim p^^sim q^^sim r The truth value of p^^sim(p^^q) is always T.

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The truth table of (~p) rArr q is

The truth table of p ^^ (~ q) is

The truth table of p ^^ q is

The truth table of (~q) rArr~ p is

The truth table of (~p) ^^ q rArr p is

The truth table of ~p) vv q is

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