7,quad d''cos3x

The values of x_1 between 0 and 2pi , satisfying the equation cos3x+cos2x=sin(3x)/2+sinx/2 are pi/7 (b) (5pi)/7 (c) (9pi)/7 (d) (13pi)/7

The values of x_1 between 0 and 2pi , satisfying the equation cos3x+cos2x=sin(3x)/2+sinx/2 are pi/7 (b) (5pi)/7 (c) (9pi)/7 (d) (13pi)/7

The number of solution in [0,pi/2] of the equation cos3x tan5x=sin7 is 5b.7c.6d none of these

(sin 7x + sin 3x )/(cos 7x + cos 3x ) = tan 5x.

Prove that (cos3x+cos7x-cos2x)/(sin 7x-sin3x-sin2x)=cot2x

Differentiate. (cos 3x-cosx)/(cos5x-cos3x)

Prove that (sin 9x+sin7+sin 3x+sin 5x)/(cos 9x+ cos 7x+ cos 3x+cos 5x)=tan 6x .

Find x cos3x+sin(2x-(7 pi)/(6))=-2