A cannon fires two shells successively with velocity `250 m s^(-1)` at angles `60^@` and `45^@` with the horizontal in the same vertical plane one after the other . What should be the interval between the firings so that they may hit the same target simultaneously ?

A cannon files successively two shells with velocity v_0=250m//s , the first at the angle theta_1=60^@ and the second at the angle theta_2=45^@ to the horizontal, the azimuth being the same. Neglecting the air drag, find the time interval between firings leading to the collision of the shells.

Two bodies are projected at angle of 45^@ and 60^@ with the horizontal with same velocity simultaneously. Ratio of their horizontal range is.

Two projectiles P and Q are fired from the same point with same velocity at angle 30^(@) and 60^(@) . The horizontal range of :

A bomb is fired from a cannon with a velocity of 1000 m/s making an angle of 30^@ with the horizontal. What is the time taken by the bomb to reach the highest point?

A bomb is fired from a cannon with a velocity of 1000 ms^(-1) making an angle of 30^(@) with the horizontal (g = 9.8 m//s^(2)). At what distance from the cannon the bomb will hit the ground?