[" 18."(5)/(x)+6y=13],[quad (3)/(x)+4y=7quad (x!=0)]

( 5)/(x) + 6y = 13, (3)/(x) + 4y = 7 ( x ne 0 )

Solve by cross-multiplication method. (i) 8x-3y=12,5x=2y +7 (ii) 6x+ 7y -11 =0, 5x+ 2y =13 (iii) (2)/(x)+(3)/(y) =5, (3)/(x) -(1)/(y) +9=0

3x-4y=-7,5x-2y=0

The equation to a pair of opposite sides of a parallelogram are x^2-5x+6=0 and y^2-6y+5=0 . The equations to its diagonals are (a) x+4y=13 ,y=4x-7 (b) 4x+y=13 ,4y=x-7 (c) 4x+y=13 ,y=4x-7 (d) y-4x=13 ,y+4x-7

If [2x+y,4x,5x-7 4x]=[7 7y-13 y x+6] , then the value of x+y is x=3 , y=1 (b) x=2 , y=3 (c) x=2 , y=4 (d) x=3 , y=3

Solve : (7 + x)/(5) - (2x - y)/(4) = 3y - 5 (5y - 7)/(2) + (4x - 3)/(6) = 18 - 5x

The equation to a pair of opposite sides of a parallelogram are x^2-5x+6=0 and y^2-6y+5=0 . The equations to its diagonals are x+4y=13 ,y=4x-7 (b) 4x+y=13 ,4y=x-7 4x+y=13 ,y=4x-7 (d) y-4x=13 ,y+4x-7

The equation to a pair of opposite sides of a parallelogram are x^2-5x+6=0 and y^2-6y+5=0 . The equations to its diagonals are x+4y=13 ,y=4x-7 (b) 4x+y=13 ,4y=x-7 4x+y=13 ,y=4x-7 (d) y-4x=13 ,y+4x-7

The equation to a pair of opposite sides of a parallelogram are x^2-5x+6=0 and y^2-6y+5=0 . The equations to its diagonals are x+4y=13 ,y=4x-7 (b) 4x+y=13 ,4y=x-7 4x+y=13 ,y=4x-7 (d) y-4x=13 ,y+4x-7

5x+7y+2=0 4x+6y+3=0