In the given figure, AM bisects angle A and DM bisects angle D of parallelogram ABCD. Prove that `angleAMD = 90^(@).`

In the figure, given below, AM bisects angle A and DM bisects angle D of parallelogram ABCD. Prove that: angleAMD= 90^(@)

In the given figure , AC gt AB and AD bisects angle BAC Prove that angle ADC gt ADB

In figure, OP bisects angle BOC and OQ bisects angle AOC , then angle POQ is

In the given figure, PS is the median, bisecting angle P, then angleQPS is

In the figure , given below , CP bisects angle ACB. Show that DP bisect angle ADB .

ABCD is a parallelogram E is mid-point of AB and DE bisects angle D. Prove that angleDEC= 90^(@)

In the given figure, PR gt PQ and PS bisects angle QPR. Prove that angle PSR gt angle PSQ .

In the given figure, PR gt PQ and PS bisects angle QPR. Prove that angle PSR gt angle PSQ .

In parallelogram ABCD, the bisectors of adjacent angles A and D intersect each other at point P. prove that angleAPD=90^(@) .

In the given figure, AB////EC,AB=AC and AE bisects angleDAC . Prove that: (i) angleEAC=angleACB (ii) ABCE is a parallelogram. .