The depth from the surface of the earth where acceleration due to gravity is `20%` of its value on the surface of the earth is (R = 6400 km)

Calculate the depth below the surface of the earth where acceleration due to gravity becomes half of its value at the surface of the earth . Radius of the earth = 6400 km.

At what depth from the surface of the earth, the acceleration due to gravity will be half the value of g on the surface of the earth ?

At what depth from the surface of the earth, the acceleration due to gravity will be half the value of g on the surface of the earth ?

If the radius of the earth is 6400 km, the height above the surface of the earth where the value of acceleration due to gravity will be 4% of its value on the surface of the earth is

At what depth below the surface does the acceleration due to gravity becomes 70% of its value in the surface of earth ?

At what depth below the surface does the acceleration due to gravity becomes 70% of its value in the surface of earth ?

At what depth below the surface does the acceleration due to gravity becomes 70% of its value in the surface of earth ?

How much below the surface of the earth does the acceleration due to gravity becomes 70% of its value at the surface of earth ? (Take R_(e)=6400 km)

If the radius of the earth is 6400 km, the height above the surface of the earth, where the value of acceleration due to gravity will be 1% of its value from the surface of the earth is