Determine the area enclosed by the curve `y=x^3` , and the lines `y=0,x=2` and x = 4.

The area enclosed by the curve xy=3 and the line y=4-x

The area enclosed by the curve xy=3 and the line y=4-x

Make a rough sketch of the graph of the function y = 4-x^2, 0 le xle 2 and determine the area enclosed between the curve and the lines x= 0, x= 2 and x-axis.

Make a rough sketch of the graph of the function y=4-x^2,\ 0lt=xlt=2 and determine the area enclosed by the curve, the x-axis and the lines x=0\ a n d\ x=2.

Make a rough sketch of the graph of the function y=4-x^2,\ 0lt=xlt=2 and determine the area enclosed by the curve, the x-axis and the lines x=0\ a n d\ x=2.

The line y=m x bisects the area enclosed by the curve y=1+4x-x^2 and the lines x=0,x=3/2 and y=0. Then the value of m is

Find the area enclosed by the curve y=-x^2 and straight line x+y+2=0.

(i) Draw a rough sketch of y = sin 2x and determine the area enclosed by the curve, x-axis and the lines x = (pi)/(4) and x = (3pi)/(4). (ii) Draw the graph of y = cos 3x, 0 lt x le (pi)/(6) and find the area between the curve and the axes.

The area enclosed between the curves y^2=4x and the line y=x is

Find the area enclosed by the curves x^2=y , y=x+2