The velocity of a freely falling body changes as `g^ph^q`where g is acceleration due to gravity and h is the height. The values of p and q are

How acceleration due to gravity changes with variation of height 'h'.

Using the dimensional method, show that the velocity v of a body falling freely under gravity varies as sqrt"gh" where g is the acceleration due to gravity and h is distance through which the body falls.

The velocity of a freely falling body is a function of the distance fallen through (h) and acceleration due to gravity g . Show by the method of dimensions that v = Ksqrt(gh) .

The velocity of a body which has fallen under gravity varies as g^(a) h^(b) where g is the acceleration due to gravity at a place and h is the height through which the body has fallen, a and b are given by

The uniform acceleration produced in a freely falling body due to gravitational pull of the earth is known as acceleration due to gravity. What is the value of g at the centre of earth?

The average velocity of a freely falling body is numerically equal to half of the acceleration due to gravity. The velocity of the body as it reaches the ground is

Find ratio of acceleration due to gravity g at depth d and at height h where d=2h

The uniform acceleration produced in a freely falling body due to gravitational pull of the earth is known as acceleration due to gravity. What is the value of acceleration due to gravity on the surface of earth.