Reduce the equation `sqrt3+y+2=0` to the normal form `x cos alpha+y sin alpha=p`, and hence find the value of `alpha and p`.

Reduce the equation x+sqrt3y-4=0 to the normal form x cos alpha+y sin alpha=p , and hence find the values of alpha and p .

Reduce the equation x+y-sqrt2=0 to the normal form x cos alpha+y sin alpha=p , and hence find the values of alpha and p .

Reduce the equation y+4=0 to the normal form x cos alhpha+y sin alpha=p and hence find the values of alpha and p .

If we reduce 3x+3y+7=0 to the form x cos alpha+y sin alpha=p, then find the value of p

Reduce the equation sqrt 3 x + y + 2 = 0 to : the normal from and find p and alpha

Reduce the equation x+y+sqrt(2)=0 to the normal form and find the value of p and alpha .

If the equation 3x + 3y + 5=0 is written in the form x cos alpha + y sin alpha = p , then the value of sin alpha + cos alpha is a) sqrt2 b) (1)/( sqrt2) c) - sqrt2 d) - (1)/( sqrt2)

If the equation 3x + 3y + 5 = 0 is written in the form x cos alpha + y sin alpha = p , then the value of sin alpha + cos alpha is

Reduce the equation of the line x cos alpha+y sin alpha-p=0 into intercepts form