The distance of a plane `Ax+By+Cz=D` from the point `(x_(1),y_(1),z_(1))` is

If the distance of the plane x - y + z + lambda = 0 from the point (1, 1, 1) is d_1 and the distance of this point from the origin is d_2 and d_2d_2 = 5 then find the value of lambda .

A plane passes through (1, - 2, 1) and is perpendicular to the planes 2x - 2y +z = 0 and x-y + 2z = 4. The distance of the plane from the point (1, 2, 2) is:

A plane passes through (1,-2,1) and is perpendicualr to two planes 2x-2y+z=0" and "x-y+2z=4, then the distance of the plane from the point (1,2,2) is

A plane passes through (1, -2, 1) and is perpendicular to two planes 2x - 2y + z=0 and x - y + 2z =4, then the distance of the plane from the point (1,2,2) is

A plane passes through (1,-2,1) and is perpendicualr to two planes 2x-2y+z=0" and "x-y+2z=4, then the distance of the plane from the point (1,2,2) is

A plane passes through (1,-2,1) and is perpendicualr to two planes 2x-2y+z=0" and "x-y+2z=4, then the distance of the plane from the point (1,2,2) is

A plane passes through (1,-2,1) and is perpendicualr to two planes 2x-2y+z=0" and "x-y+2z=4, then the distance of the plane from the point (1,2,2) is