In the adjoining figure, the diagonals AC and BD of a quadrilateral ABCD intersect at O.
If ` BO = OD`, prove that
`ar(triangleABC)=ar(triangleADC)`.

In the adjoining figure, the diagonals AC and BD of a quadrilateral ABCD intersect point O. Prove that : AB+BC+CD+DA lt 2(AC+BD)

In the adjoining figure, the diagonals AC and BD of a quadrilateral ABCD intersect point O. Prove that : AB+BC+CD+DA lt 2(AC+BD)

The diagonals AC and BD of a quadrilateral ABCD intersect at point 'O'. If BO = OD, then prove that the areas of Delta ABC and Delta ADC are equal

In the figure, diagonals AC and BD of quadrilateral ABCD intersect at O such that OB = OD. If AB = CD, then show that ar( Delta DOC) = ar( Delta AOB)

Diagonals AC and BD of quadrilateral ABCD interset at O such that OB = OD , If AB = Cd, then show that : ar(DCB) = ar(ACB)

In the figur e, diagonals AC and BD of quadrilateral A BCD intersect at 0 such that OB = OD. If AB = CD, then show that ar( Delta DCB) = ar( Delta ACB)

In Fig 9.25 ,diagonals AC and BD of quadrilateral ABCD intersect at O such that OB= OD.If AB=CD, then show that

In the given figure, diagonals AC and BD of quadrilateral ABCD interset at O such that OB = OD. If AB = CD, then show that : (i) ar (DOC) = ar (AOB) (ii) ar (DCB) = ar (ACB) (iii) DA || CB or ABCD is a parallelogram .

Diagonals AC and BD of a quadrilateral intersect at O. It AO:OC=1:2=BO:ODandAB=16cm then DC is

Diagonals AC and BD of a quadrilateral ABCD intersect at O in such a way that ar (AOD)=ar(BOC). Prove that ABCD is a trapezium.