If `a=(b+c)costheta` then show that `sintheta=(2sqrt(bc))/(b+c)cos (A/2)`

If a=(b+c)costheta, " then prove that" sintheta=(2sqrt(bc))/(b+c)cos((A)/(2))

If sin theta = a/(b+c) then show that cos theta = (2sqrt(bc))/(b+c) cos ((A)/(2))

If a costheta-b sintheta=c ,show that a sintheta+bcostheta=+-sqrt(a^2+b^2-c^2)

If sintheta +costheta =sqrt(2) costheta then prove that costheta -sintheta=sqrt(2) sintheta

sintheta+costheta=sqrt(2)

If a cos theta-b sin theta=c, show that a sin theta+b cos theta=+-sqrt(a^(2)+b^(2)+c^(2))

If costheta+sintheta=sqrt2costheta ,then show that costheta-sintheta=sqrt2 sintheta .

If cos theta -sin theta =sqrt(2) sin theta , show that, costheta+sintheta=sqrt(2) cos theta [0ltthetaltpi/2] .