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The displacement of a body is given by s=(1)/(2)g t^(2) where g is acceleration due to gravity. The velocity of the body at any time t is

The displacement of a body is given by s=(1)/(2)g t^(2) where g is acceleration due to gravity. The velocity of the body at any time t is

The displacement of a body is given by 2 s= g t^(2) where g is a constant. The velocity of the body at any time t is :

The displacement of body is given by s = 4 + 2t^4 . The acceleration of the body at the end of 1 s from the start is :

The height reached in time t by a particle thrown upward with a speed u is given by h=ut-(1)/(2) "gt"^(2) where g is acceleration due to gravity. Find the time taken in reaching the maximum height.

The displace ment of a body at any time t after starting is given by s=10t-(1)/(2)(0.2)t^2 . The velocity of the body is zero after:

The displace ment of a body at any time t after starting is given by s=10t-(1)/(2)(0.2)t^2 . The velocity of the body is zero after:

The distance S an object travles under the influence of gravity in time t seconds is given by S(t)=(1)/(2)"gt"^(2)+at+b where, (g is the acceleration due to gravity), a, b, are constants. Check if the function S(t) is one-one.