If `tan(pi/4+theta/2)=tan^3(pi/4+alpha/2)` then `sin(theta)=(sin(alpha)(3+sin^2(alpha)))/(1+3sin^2(alpha))`

If tan^(3) (alpha/2+ pi/4) = tan(beta/2 +pi/4) then prove that sin beta = ((3 + sin^(2)alpja) sin alpha) /(1 + 3sin^(2)alpha)

Show that 4sin alpha*sin(alpha+(pi)/(3))sin(alpha+2(pi)/(3))=sin3 alpha

If tan (alpha+theta)=n tan (alpha-theta) ,show that: (n+1)"sin" 2theta=(n-1) sin 2alpha

sin alpha+sin(alpha+((2pi)/3))+sin(alpha+((4pi)/3))=0

prove that 4sin alpha*sin(alpha+(pi)/(3))*sin(alpha+(2 pi)/(3))=sin3 alpha

prove sin alpha+sin(alpha+(2pi)/3)+sin (alpha+(4pi)/3)=0

Prove that sin alpha+sin(alpha+2pi/3)+sin(alpha+4pi/3)=0

If tan(alpha+theta)=n tan(alpha-theta), show that (n+1)sin2 theta=(n-1)sin2 alpha.

If tan theta = ( tan alpha - tan beta)/(1-tan alpha tan beta),"show that", sin 2 theta=(sin 2 alpha- sin 2 beta)/(1- sin2 alpha sin 2 beta).

If tan 2 theta=sec2 alpha, prove that sin2 theta=(1-tan^(4)alpha)/(1+tan^(4)alpha)