` cos.((3pi)/2+x)cos.(2pi+x)`
` [ cot((3pi)/2-x)+cot(2pi+x)]=1`

Prove that: cos((3 pi)/(2)+x)cos(2pi+x)[cot((3 pi)/(2)-x)+cot(2 pi+x)]=1

The value of cos ((3pi)/2 + x)cos (2pi + x){cot ((3pi)/2 - x) + cot (2pi + x)} is-

Prove that: cos((3 pi)/(2)+x)cos(2 pi+x){cot((3 pi)/(2)-x)+cot(2 pi+x)}=1

The value of "cos"((3pi)/2+x)."cos"(2pi+x)["cot"((3pi)/(2)-x)+"cot"(2pi+x)] is

(sin (pi + x) cos ((pi) / (2) + x) tan ((3 pi) / (2) -x) cot (2 pi-x)) / (sin (2 pi-x) cos (2 pi + x) csc (-x) sin ((3 pi) / (2) -x)) = 1

cos ((3pi)/(2)+theta) cos (2pi+theta) xx [ cot ((3pi)/(2) -theta) + cot (2pi + theta) ] = ?

(cos (pi +x) cos (-x))/( sin (pi -x) cos ((pi )/(2) + x))= cot ^(2) x

(cos (pi +x) cos (-x))/( sin (pi -x) cos ((pi )/(2) + x))= cot ^(2) x

(cos (pi +x) cos (-x))/( sin (pi -x) cos ((pi )/(2) + x))= cot ^(2) x