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" (B) "(sqrt(12))/(sqrt(3))...

" (B) "(sqrt(12))/(sqrt(3))

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12.Rationalise and find the value of' "a'" and "'b'" ; (i) "(sqrt(3)-1)/(sqrt(3)+1)=a+b sqrt(3), (ii) (sqrt(5)-2)/(sqrt(5)+2)=a+b sqrt(5)

Simplify- (3*sqrt(2)-2*sqrt(3))/(3*sqrt(2)+2*sqrt(3))+(sqrt(12))/(sqrt(3)-2)

(3sqrt(2)-2sqrt(3))/(3sqrt(2)+2sqrt(3))+(sqrt(12))/(sqrt(3)-sqrt(2))

Simplify: (3sqrt(2)-2sqrt(2))/(3sqrt(2)+2sqrt(3))+(sqrt(12))/(sqrt(3)-sqrt(2)) (ii) (sqrt(5)+sqrt(3))/(sqrt(5)-sqrt(3))+(sqrt(5)-sqrt(3))/(sqrt(5)+sqrt(3))

Simplify: (i) (3sqrt(2)-2sqrt(2))/(3sqrt(2)+\ 2sqrt(3))+(sqrt(12))/(sqrt(3)-\ sqrt(2)) (ii) (sqrt(5)+\ sqrt(3))/(sqrt(5)-\ sqrt(3))+(sqrt(5)-\ sqrt(3))/(sqrt(5)+\ sqrt(3))

If A(1,-1,2),B(2,1,-1)C(3,-1,2) are the vertices of a triangle then the area of triangle ABC is (A) sqrt(12) (B) sqrt(3) (C) sqrt(5) (D) sqrt(13)

(sqrt(3)+1)(1-sqrt(12))+(9)/(sqrt(3)+sqrt(12))

If x= (4sqrt(15))/(sqrt5+sqrt3) , then (x+sqrt(20))/(x-sqrt(20))+(x+sqrt(12))/(x-sqrt(12))= ?