Recommended Questions
- सिद्ध कीजिए की: sin ^(2) ( n+1) A - sin ^(2) nA =sin (2n +1) A sin ...
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- sin(2n+1)A*sin A=sin^(2)(n+1)A-sin^(2)(nA)
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- Prove that: sin^2(n+1)A-sin^2n A="sin"(2n+1)A s in A
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- sin a + sin2a + sin3a + ... + sin na = (sin (((n + 1) a) / (2)) sin ((...
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- sin A+sin3A+...+sin(2n-1)A=(sin^(2)nA)/(sin A)
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- सिद्ध कीजिए की: (i) sin (2n +1) A . sin A = sin ^(2) (n+1) A - sin ^(...
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- lim( n to oo) (sin ""(pi)/(2n) . sin ""(2pi)/(2n). sin ""(3pi)/(2n)......
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- सिद्ध कीजिए की: sin ^(2) ( n+1) A - sin ^(2) nA =sin (2n +1) A sin ...
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- Evaluate : underset(n to oo)lim (1)/(n)[sin (pi/(2n))+sin((2pi)/(2n)...
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