If `(6^(n))/(6^(-2))=6^(3)`, then n=?

Find the value of n. (6^(n))/(6^(-2))=6^(3)

If (n-1)C_(6)+(n-1)C_(7)>nC_(6) then

The value of (6^(n+3) - 32.6^(n+1))/(6^(n+2) - 2.6^(n+1)) is equal to

Find the sum sum_(n=1)^(oo)(6^(n))/((3^(n)-2^(n))(3^(n+1)-2^(n+1)))

(6^(n+3)-32*6^(n+1))/(6^(n+2)-2*6^(n+1))=1

If n/2 - (3n)/4 + (5n)/6 = 21 , then n = ?

If (1+ax)^(n)=1+6x+(27)/(2)x^(2)+....+a^(n)x^(n) then the value of a and n are respectively (i) 2,3( ii) 3,2( iii) (3)/(2),4( iv )1,6( v) (3)/(2),6