Home
Class 12
PHYSICS
A wire is bent in the form of a V shape...

A wire is bent in the form of a `V` shape and placed in a horizontal plane.There exists a uniform magnetic field `B` perpendicular to the plane of the wire. A uniform conducting rod starts sliding over the `V` shaped wire with a constant speed v as shown in the figure. If the wire no resistance, the current in rod wil

A

Increase with time

B

Decrease with time

C

Remain constant

D

Always be zero.

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • PHYSICS PART2

    FIITJEE|Exercise Section (I) : Subjective|4 Videos

  • PHYSICS PART2

    FIITJEE|Exercise Section (II) : MCQ|27 Videos

  • PHYSICS PART-III

    FIITJEE|Exercise NUMERICAL BASED QUESTIONS DECIMAL TYPE|11 Videos

  • ROTATIONAL MECHANICS

    FIITJEE|Exercise COMPREHENSION - IV|2 Videos

Similar Questions

Explore conceptually related problems

In the figure shown as uniform magnetic field |B|=0.5T is perpendicular to the plane of circuit. The sliding rod of length l=0.25 m moves uniformly with constant speed v=4ms^-1 . If the resistance of the sllides is 2Omega , then the current flowing through the sliding rod is

A flexible wire bent in the form of a circle is placed in a uniform magnetic field perpendicular to the plane of the coil. The radius of the coil changing as shown in figure. The graph of induced emf in the coil is represented by

A wire bent as a parabola y=kx^(2) is located in a uniform magnetic field of induction B, the vector B being perpendicular to the plane xy. At t=0 , the sliding wire starts sliding from the vertex O with a constant acceleration a linearly as shown in Fig. Find the emf induced in the loop -

A circular loop of wire is carring a current i (as shown in the figure). On applying a uniform magnetic field inward perpendicular to the plane of the loop, the loop

Imagine a would where free magnetic charges exist. In this world, a circuit is made with a U shape wire and a rod free to slide on it. A current carried by free magnetic charges can flow in the circuit. When the circuit is placed in a uniform electric field. E perpendicular to the plane of the plane of the circuit and the rod is pulled to the right with a constant speed v, the "magnetic EMF" in the current and the direction of the corresponding current. arising because of changing electric flux will be (l is the length of the rod and c is speed of light).

A wire is bent to form the double loop shown in figure. There is a uniform magnetic field directed into the plane of the loop. If the magnitude of this field is decreasing current will flow from:

A rod PQ is connected to the capacitor plates. The rod is placed in a magnetic field (B) directed downwards perpendicular to the plane of the paper. If the rod is pulled out of magnetic field with velocity vec(v) as shown in Figure.

A small conducting rod of length l, moves with a uniform velocity v in a uniform magnetic field B as shown in fig __