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The charges on the two plates initially ...

The charges on the two plates initially (at = 0) are `Q_1` and `Q_2` . Long time after closing the key, the charges on the outer and Inner of plate 1 are, respectively (C = capacitance of capacitor )

A

`Q_1,0`

B

`(Q_1+Q_2)/2, Cepsilon`

C

`(Q_1-Q_2)/2 , -Cepsilon`

D

`(Q_1+Q_2)/2, (Q_1-Q_2)/2`

Text Solution

Verified by Experts

The correct Answer is:
B
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