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The minimum intensity of audibility of s...

The minimum intensity of audibility of sound is `10^(-12) W//m^(2) s` and density of air ` = 1.293 kg//m^(3)`. If the frequency of sound in `1000 Hz` , then the corresponding amplitude the vibration of the air particles is
[ Take velocity of sound `= 332 m//s`]

A

`1.1 xx10^(-7)`m

B

`1.1 xx10^(-9)`m

C

`1.1 xx10^(-11)` m

D

`1.1 xx10^(-8)`m

Text Solution

Verified by Experts

The correct Answer is:
C
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