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Find the maximum kinetic enegry of photoelectrons liberated form the surface of lithium by electromagnetic radiation whose electric component varies with time as `E = a(1+cos omegat) cos omega_(0)t`, where `a` is a constant, `omega = 6.10^(14)s^(-1)` and `omega_(0) = 360.10^(15)s^(-1)`.(Work function of Lithiuim = 2.39eV)

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The correct Answer is:
0.37 eV
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