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A sonometer wire 64 cm long produces 8 b...

A sonometer wire 64 cm long produces 8 beats per second with a tuning fork. If length of sonometer wire is increased by one centimeter it resonates with the tuning fork. The frequency of tuning fork is observed 64x . The value of x is

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To solve the problem step-by-step, we will use the relationship between the frequencies of the sonometer wire and its lengths, along with the concept of beats. ### Step 1: Understand the relationship between frequency and length The frequency of a vibrating wire is inversely proportional to its length when the tension and mass per unit length are constant. This can be expressed as: \[ \frac{N_1}{N_2} = \frac{L_2}{L_1} \] where \(N_1\) and \(N_2\) are the frequencies corresponding to lengths \(L_1\) and \(L_2\), respectively. ### Step 2: Define the lengths Given: - Initial length \(L_1 = 64 \, \text{cm}\) - Increased length \(L_2 = L_1 + 1 \, \text{cm} = 65 \, \text{cm}\) ### Step 3: Set up the frequency ratio Using the relationship: \[ \frac{N_1}{N_2} = \frac{65}{64} \] ### Step 4: Understand the beats produced The problem states that 8 beats per second are produced when the sonometer wire is at 64 cm. The number of beats is given by: \[ |N_1 - N_2| = 8 \] Since \(N_1\) is greater than \(N_2\) (because the length increased), we can write: \[ N_1 - N_2 = 8 \] ### Step 5: Express \(N_1\) in terms of \(N_2\) From the beats equation: \[ N_1 = N_2 + 8 \] ### Step 6: Substitute \(N_1\) into the frequency ratio Now substitute \(N_1\) into the frequency ratio: \[ \frac{N_2 + 8}{N_2} = \frac{65}{64} \] ### Step 7: Cross-multiply to solve for \(N_2\) Cross-multiplying gives: \[ 64(N_2 + 8) = 65N_2 \] Expanding this: \[ 64N_2 + 512 = 65N_2 \] ### Step 8: Rearrange to find \(N_2\) Rearranging gives: \[ 65N_2 - 64N_2 = 512 \] \[ N_2 = 512 \, \text{Hz} \] ### Step 9: Relate \(N_2\) to the tuning fork frequency According to the problem, the frequency of the tuning fork is given by: \[ N_2 = 64x \] Thus, we can set up the equation: \[ 64x = 512 \] ### Step 10: Solve for \(x\) Dividing both sides by 64: \[ x = \frac{512}{64} = 8 \] ### Final Answer The value of \(x\) is \(8\). ---
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