A simple pendulum has time period T when on the earth's surface and `T_(2)` when taken in a tunnel at depth 3R/4 along the diameter of earth, where R is the radius of earth. The value of `T_(2)//T_(1)`

Explanation

To solve the problem of finding the ratio \( \frac{T_2}{T_1} \) for a simple pendulum at the Earth's surface and at a depth of \( \frac{3R}{4} \), we can follow these steps:

### Step 1: Understand the Time Period of a Simple Pendulum
The time period \( T \) of a simple pendulum is given by the formula:
\[ T = 2\pi \sqrt{\frac{L}{g}} \]
where \( L \) is the length of the pendulum and \( g \) is the acceleration due to gravity.
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