3000 J of heat is given to a gas at a constant pressure of `2xx10^(5)N//m^(2)`.If its volume increase bny 10 litres during the process find the change in the intrnal energy of the gas.

Explanation

To solve the problem, we need to find the change in the internal energy of the gas when 3000 J of heat is added at a constant pressure of \(2 \times 10^5 \, \text{N/m}^2\) and the volume increases by 10 liters.

### Step-by-step Solution:

1. **Identify Given Values:**
- Heat added to the gas, \( \Delta Q = 3000 \, \text{J} \)
- Pressure, \( P = 2 \times 10^5 \, \text{N/m}^2 \)
- Volume change, \( \Delta V = 10 \, \text{liters} = 10 \times 10^{-3} \, \text{m}^3 = 10^{-2} \, \text{m}^3 \)
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