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A room heater is made up of thin wall tu...

A room heater is made up of thin wall tubes of copper, each 1.0 m long and 4.0 cm in diameter. Hot water aet `77^(@)C` circulates constantlyh through the tubes. Calculate the amount of heat radiated per second in a room where the average temperature is `27^(@)C`. The emissivity of copper =0.8 and Stefan's contant `=5.67xx10^(-8)Wm^(-2)K^(-1)`

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To solve the problem of calculating the amount of heat radiated per second by a room heater made of copper tubes, we will follow these steps: ### Step 1: Understand the given data - Length of each tube, \( L = 1.0 \, \text{m} \) - Diameter of each tube, \( d = 4.0 \, \text{cm} = 0.04 \, \text{m} \) - Radius of each tube, \( r = \frac{d}{2} = 0.02 \, \text{m} \) - Temperature of hot water, \( T = 77^\circ C = 77 + 273 = 350 \, K \) - Average temperature of the room, \( T_0 = 27^\circ C = 27 + 273 = 300 \, K \) ...
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