Calculate the escape velocity of a body from the moon. [g(moon)`=1.67m//s^(2),` R(moon) `=1.74xx10^(6)m`]

Explanation

`v_(rms)=sqrt((3kT)/m)` and the escape velocity is give by `v_(e)=sqrt(2gR)`
If `v_(rms)=v_(e)`
`sqrt((3kT)/m)=sqrt(2gR)impliesT(2mgR)/(3k)`
`=2/3xx(((2xx10^(-3))/(6.02xx10^(23)))xx1.67xx1.74xx10^(8))/(1.38xx10^(-23))=466K`