Home
Class 12
PHYSICS
The average translational energy and the...

The average translational energy and the rms speed of molecules in a sample of oxygen gas at `300K` are `6.21xx10^(-21)J` and `484m//s`, respectively. The corresponding values at `600K` are nearly (assuming ideal gas behaviour)

A

`12.42xx10^(-21)` , 968 m/s

B

`6.21xx10^(-21)J,968` m/s

C

`8.78xx10^(-12)J, 684` m/s

D

`12.42xx10^(-21)J, 684` m/s

Text Solution

Verified by Experts

`KE=3/2 kT`
`v_(rms)=sqrt((3RT)/M)`
ie. `(KE_(2))/(KE_(1))=(T_(2))/(T_(1))=2`
`KE_(2)=2KE_(1)=2xx6.21xx10^(-21)=12.42xx10^(-21)J`
`(v_(rms,2))/(v_(rms,1))=sqrt((T_(2))/(T_(1)))=sqrt(2)`
`:.v_(rms,2)=sqrt(2)xxv_(rms,1)=684` m/s
Hence d is correct
Promotional Banner

Topper's Solved these Questions

  • HEAT AND TEMPERATURE

    FIITJEE|Exercise COMPREHENSION TYPE|5 Videos

  • HEAT AND TEMPERATURE

    FIITJEE|Exercise ASSERTION REASON TYPE|1 Videos

  • HEAT AND TEMPERATURE

    FIITJEE|Exercise SOLVED PROBLEMS SUBJECTIVE|18 Videos

  • GRAVITATION

    FIITJEE|Exercise Numerical based Question|2 Videos

  • KINEMATICS

    FIITJEE|Exercise NUMERICAL BASED QUESTIONS DECIMAL TYPE|5 Videos

Similar Questions

Explore conceptually related problems

The average rms speed of molecules in a sample of oxygen gas at 300 K is 484ms^(-1) ., respectively. The corresponding value at 600 K is nearly (assuming ideal gas behaviour)

The average energy of molecules in a sample of oxygen gas at 300 K are 6.21xx10^(-21)J . The corresponding values at 600 K are

find the rms speed of oxygen molecules in a gas at 300K.

The average translational K.E. of the molecules in a sample of oxygen at 300K is 6xx10^(-20)J . What is the average translational energy at 750 K?

The R.M.S . Speed of the molecules of a gas of density kg m^(-3) and pressure 1.2xx10^(5)Nm^(-2) is:

Average translational kinetic energy of an ideal gas molecule at 27^(@) C is 3.88 xx 10^(-x) eV . Hence x is :

The average kinetic energy of the molecules of a gas at 27^(@) is 9xx10^(-20)J . What is its average K.E. at 227^(@)C ?

The average translational kinetic energy of nitrogen gas molecule is 0.02eV (1eV - 1.6 xx 10^(-19)J) . Calculate the temperatuire of the gas. Boltzmann constant k = 1.38 xx 10^(-23) J//K .

The number of molecules in one litre of an ideal gas at 300 K and 2 atmospheric pressure with mean kinetic energy 2xx10^(-9) J per molecules is :