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A gas undergoes cyclic process 1-2-3-4-1...

A gas undergoes cyclic process 1-2-3-4-1 in which 1-2 and 3-4 are adiabatic process 2-3 and 4-1 are isobaric process. If `(P_(2))/(P_(1))=k` then what will be the efficiency of cycle in terms of k and `gamma` where `gamma=C_(p)//C_(v)`.

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The correct Answer is:
`eta=1- 1/(k^((gamma-1)/(gamma)))`
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