The coil of a galvanometer has 500 turn and each turn has an average area of `3 xx 10^(-4) m^(2)`. Calculate the magnetic moment of the coil when a current of 0.5 A passes through it. If a torque of 1.5 Nm is required for this coil carrying same current to set it parallel to a magnetic field. calculate the strength of the magnetic field.
Text Solution
AI Generated Solution
To solve the problem step by step, we will break it down into two parts: calculating the magnetic moment of the coil and then calculating the strength of the magnetic field.
### Step 1: Calculate the Magnetic Moment (μ) of the Coil
The formula for the magnetic moment (μ) of a coil is given by:
\[
\mu = n \cdot I \cdot A
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