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A charged particle moves in a uniform ma...

A charged particle moves in a uniform magnetic field perpendicular to it, with a radius of curvature 4 cm. On passing through a metallic sheet it loses half of its kinetic energy. Then, the radius of curvature of the particle is

A

2cm

B

4 cm

C

8 cm

D

`2 sqrt(2)` cm

Text Solution

Verified by Experts

The correct Answer is:
D
`R = (mv)/(qB) = (m)/(qB) sqrt((2(KE))/(m)) = (sqrt(2m))/(qB) = sqrt(KE)`
`implies (R_(1))/(R_(2)) = (sqrt(KE))/(sqrt(KE//2))`
`implies R_(2) = (R_(1))/(sqrt(2)) = (4)/(sqrt(2)) = 2 sqrt(2) cm`
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