Home
Class 12
PHYSICS
A current I is flowing in a conductor ...

A current I is flowing in a conductor of length L when it is bent in the form of a circular loop its magnetic moment

Text Solution

Verified by Experts

`M = pi r^(2) I`
`2 pi r = L`
`M = (pi L^(2))/(4 pi^(2)) | = (L^(2)|)/(4 pi)`
Promotional Banner

Topper's Solved these Questions

  • MAGNETIC

    FIITJEE|Exercise Assignment Problems (Subjective) (Level-I)|15 Videos
  • MAGNETIC

    FIITJEE|Exercise Assignment Problems (Subjective) (Level - II & III)|15 Videos
  • MAGNETIC

    FIITJEE|Exercise Matrix match Type|8 Videos
  • LAWS OF MOTION

    FIITJEE|Exercise COMPREHENSION-III|2 Videos
  • MAGNETISM

    FIITJEE|Exercise Example|12 Videos

Similar Questions

Explore conceptually related problems

When a magnet is bent into the form of 'L' , its magnetic moment ______

An iron rod of length L and magnetic moment M is bent in the form of a semicircle. Now its magnetic moment will be

A current I flows in a conducting wire of lenth L. If we bent it in a circular form, then calculate its magnetic dipole moment.

A straight steel wire of length l has a magnetic moment M. When it is bent in the form of a semi - circle its magnetic moment will be

One of the two identical conducting wires of length L is bent in the form of a circular loop and the other one into a circular coil of N identical turns. If the same current passed in both, the ratio of the magnetic field at the central of the loop (B_(L)) to that at the central of the coil (B_(C)) , i.e. (B_(L))/(B_(C)) will be :

A bar magnet of magnetic moment M is bent in the form of quadrant of circular arc . The new magnetic moment is

The wire of length L is bent in the form of square and circle.The ratio of their magnetic moment at their centre is

A wire of length L metre carrying a current of I ampere is bent in the form of a circle. Find its magnetic moment.