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A circular coil of radius r carries I. I...

A circular coil of radius r carries I. If the same coil is now changed into a square loop carrying the same current, magnitude of its magnetic moment will

A

increase

B

decrease

C

remain constant

D

changes depending upon the value of r

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The correct Answer is:
To solve the problem of finding the change in the magnetic moment when a circular coil is transformed into a square loop while maintaining the same current, we can follow these steps: ### Step 1: Understand the Magnetic Moment Formula The magnetic moment \( m \) of a coil is given by the formula: \[ m = n \cdot I \cdot A \] where: - \( n \) = number of turns (assumed to be 1 in this case), - \( I \) = current flowing through the coil, - \( A \) = area of the loop. ### Step 2: Calculate the Magnetic Moment of the Circular Coil For a circular coil of radius \( r \), the area \( A \) is: \[ A = \pi r^2 \] Thus, the magnetic moment \( m \) for the circular coil becomes: \[ m = 1 \cdot I \cdot \pi r^2 = I \pi r^2 \] ### Step 3: Convert the Circular Coil to a Square Loop When the circular coil is transformed into a square loop, the length of wire remains the same. The circumference of the circular coil is: \[ C = 2\pi r \] For a square loop, if the side length is \( a \), the perimeter is: \[ P = 4a \] Setting the two equal gives: \[ 2\pi r = 4a \implies a = \frac{\pi r}{2} \] ### Step 4: Calculate the Area of the Square Loop The area \( A \) of the square loop is: \[ A = a^2 = \left(\frac{\pi r}{2}\right)^2 = \frac{\pi^2 r^2}{4} \] ### Step 5: Calculate the Magnetic Moment of the Square Loop Using the area calculated, the magnetic moment \( m' \) for the square loop is: \[ m' = 1 \cdot I \cdot \frac{\pi^2 r^2}{4} = I \frac{\pi^2 r^2}{4} \] ### Step 6: Compare the Magnetic Moments Now we compare \( m' \) with \( m \): \[ \frac{m'}{m} = \frac{I \frac{\pi^2 r^2}{4}}{I \pi r^2} = \frac{\frac{\pi^2}{4}}{\pi} = \frac{\pi}{4} \] This shows that: \[ m' = m \cdot \frac{\pi}{4} \] Since \( \frac{\pi}{4} < 1 \), it indicates that the magnetic moment of the square loop is less than that of the circular coil. ### Conclusion The magnitude of the magnetic moment decreases when the circular coil is changed into a square loop while maintaining the same current.
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