A current of 1 A flows a wire of length 0.1 m in a magnetic field of 0.5 T. The force acting on the wire when it makes an angle of `90^(@)` with the field is

Options

A. zero
B. 0.05 N
C. 1 N
D. 0.5 N

Answer

To solve the problem of finding the force acting on a wire carrying a current in a magnetic field, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Given Values:**
- Current (I) = 1 A
- Length of the wire (L) = 0.1 m
- Magnetic field strength (B) = 0.5 T
- Angle (θ) = 90° (since the wire is perpendicular to the magnetic field)

2. **Use the Formula for Magnetic Force:**
The force (F) acting on a current-carrying wire in a magnetic field is given by the formula:
\[ F = I \cdot L \cdot B \cdot \sin(\theta) \]

3. **Substitute the Values into the Formula:**
Since θ = 90°, we know that \(\sin(90°) = 1\). Therefore, the formula simplifies to:
\[ F = I \cdot L \cdot B \]

Now substituting the known values:
\[ F = 1 \, \text{A} \cdot 0.1 \, \text{m} \cdot 0.5 \, \text{T} \]

4. **Calculate the Force:**
\[ F = 1 \cdot 0.1 \cdot 0.5 = 0.05 \, \text{N} \]

5. **Conclusion:**
The force acting on the wire is **0.05 N**.