Home
Class 12
PHYSICS
The magnetic field at the origin due to ...

The magnetic field at the origin due to a current element `I vec(dl)` placed at position `r` is
(i) `((mu_(0)i)/(4pi))((dvec(l)xxvec(r))/(r^(3)))`
`-((mu_(0)i)/(4pi))((dvec(l)xxvec(r))/(r^(3)))`
(iii) `((mu_(0)i)/(4pi))((vec(r)xxdvec(l))/(r^(3)))`
`-((mu_(0)i)/(4pi))((vec(r)xxdvec(l))/(r^(3)))`

A

`(mu_(0) I d vec(l) xx vec(r ))/(4 pi r^(2))`

B

`(mu_(0) I vec(r ) xx d vec(l))/(4 pi r^(2))`

C

`(mu_(0) I vec(r ) xx d vec(l))/(4 pi r^(2))`

D

`- (mu_(0) I d vec(l) xx vec(r ))/(4pi r^(2))`

Text Solution

Verified by Experts

The correct Answer is:
C, D
Promotional Banner

Topper's Solved these Questions

  • MAGNETIC

    FIITJEE|Exercise Comprehension -1|3 Videos

  • MAGNETIC

    FIITJEE|Exercise Comprehension -2|3 Videos

  • MAGNETIC

    FIITJEE|Exercise Assignment Problems (Assertion Reasoning Type)|2 Videos

  • LAWS OF MOTION

    FIITJEE|Exercise COMPREHENSION-III|2 Videos

  • MAGNETISM

    FIITJEE|Exercise Example|12 Videos

Similar Questions

Explore conceptually related problems

The magnetic field at the origin due to a current element I (vec dl ) placed at a positon (vec r) is

The magnetic field bar(dB) due to a small current element bar(dl) at a distance vec(r) and carrying current 'I' is

The magnetic induction at centre of loop due to current flowing through small element 'dl' is given as dB = mu_(0)/(4pi)(Idl sin theta)/r^(2) where theta is

The vector form of Coulomb's law is (A) vec F=(1)/(4 pi epsilon_(0))*(q_(1)q_(2))/(|vec r|^(3))vec r (B) vec F=(1)/(4 pi epsilon_(0))*(q_(1)q_(2))/(|vec r|^(3)) (C) vec F=(1)/(4 pi epsilon_(0))*(q_(1)q_(2))/(r^(2))vec r (D) vec F=(1)/(4 pi epsilon_(0))*(q_(1)q_(2))/(r)vec r

The earth may be considered to be a big dipole of moment 6.4 xx 10^(12)Am placed at its centre with its axis in the SN direction. The radius of the earth is 6000 km. Calculate the horizontal and vertical components of the earth's magnetic field at a place whose lattitude is 22^(@)N . [Hint: B_(r) = (mu_(0))/(4pi) (2m cos theta)/(r^(3)) and B_(theta) = (mu_(0))/(4pi)(m sin theta)/(r^(3)) , here theta = 90^(@) +22^(@) = 112^(@) ]

The vector form of Coulomb's law is (A) vec F=(1)/(4 pi epsilon_(0))*(q_(1)q_(2))/(|vec r|^(3))vec r (B) vec F=(1)/(4 pi epsilon_(0))*(q_(1)q_(2))/(r^(3)) (C) vec F=(1)/(4 pi epsilon_(0))*(q_(1)q_(2))/(r^(2))vec r (D) vec F=(1)/(4 pi epsilon_(0))*(q_(1)q_(2))/(r)vec r

vec(r)=2that(i)+3tvec(2)hat(j) . Find vec(v) and vec(a) where vec(v)=(dvec(r))/(dr) , vec(a)=(dvec(v))/(dt)

In the given loop the magnetic field at the centre O is 1) (mu_0I)/(4) ( (r_1 + r_2)/(r_1 r_2) ) out of the page 2) (mu_0I)/(4) ( (r_1 + r_2)/(r_1 r_2)) into the page 3) (mu_0I)/(4) ( (r_1 - r_2)/(r_1 r_2)) out of the page 4) (mu_0 I)/(4) ( (r_1 - r_2)/(r_1r_2) ) into the page

FIITJEE-MAGNETIC-Assignment Problems (Level - II)
  1. A positively charged particle is moving along the positive X-axis.You ...

    Text Solution

    |

  2. The magnetic field at centre of a hexagonal coil of side l carrying a ...

    Text Solution

    |

  3. A conductor AB of length L carrying a current I', is placed perpendicu...

    Text Solution

    |

  4. A current I flows along a thin wire shaped as shown in figure. The rad...

    Text Solution

    |

  5. A charged particle is released from rest in a region of steady and uni...

    Text Solution

    |

  6. A proton moving with a constant velocity passes through a region of sp...

    Text Solution

    |

  7. A coaxial cable consists of a thin inner current carrying conductor fi...

    Text Solution

    |

  8. A charged particle having kinetic energy E enters normally a region of...

    Text Solution

    |

  9. Electric and magnetic field are directed as E(0) hat(i) and B(0) hat(k...

    Text Solution

    |

  10. A charged paricle goes undeflected in a region containing electric an...

    Text Solution

    |

  11. A long, straight wire of radius R carries a current distributed unifor...

    Text Solution

    |

  12. A long, straight wire carries a current along the z-axis. One can find...

    Text Solution

    |

  13. A hollow tube is carrying an electric current along its length distrib...

    Text Solution

    |

  14. The magnetic field at the origin due to a current element I vec(dl) pl...

    Text Solution

    |

  15. Two charged particle M and N are projected with same velocity in a uni...

    Text Solution

    |

  16. An observer A and a charge Q are fixed in a stationary frame F(1). An...

    Text Solution

    |

  17. A long straight wire carries the current along +ve x-direction. Consid...

    Text Solution

    |

  18. In the previous question if the current is I and the magnetic field at...

    Text Solution

    |

  19. L is a circular ring made of a uniform wire, currents enters and leave...

    Text Solution

    |

  20. In the loops shown in fig. all curved section are either semicircles o...

    Text Solution

    |