Home
Class 12
PHYSICS
Shown in the Fig. is a shperical surface...

Shown in the Fig. is a shperical surface of radius of curvature R and R.I. `(=n)1.5`. Find the distance of the silvering of the plane surface so as to form an image at the pole due to a very far object.

Text Solution

Verified by Experts

Since light comes from very distant object
` u=infty`
`implies mu/v - 1/oo = (mu-1)/R`
`implies v = (muR)/(mu-1) = (1.5R)/(1.5-1) =3R`
Due to presence of the plane mirror, the image formed at I behaves as a virtual object for the plane mirror & a real image I’ is formed in front of the plane mirror, at the pole P.
`implies x+x=v`
`x = v/2 =(3R)/2 = 1.5R`
Promotional Banner

Topper's Solved these Questions

  • OPTICS

    FIITJEE|Exercise SOLVED PROBLEMS (SUBJECTIVE)|18 Videos

  • OPTICS

    FIITJEE|Exercise Solved problem (objective)|15 Videos

  • OPTICS

    FIITJEE|Exercise NUMERICAL BASED QUESTIONS|2 Videos

  • MODERN PHYSICS

    FIITJEE|Exercise Numerical based questions|5 Videos

  • PHYSICS PART-III

    FIITJEE|Exercise NUMERICAL BASED QUESTIONS DECIMAL TYPE|11 Videos

Similar Questions

Explore conceptually related problems

A denser medium of refractive index 1.5 has a concave surface of radius of curvature 12 cm. An object is situated in the denser medium at a distance of 9 cm from the pole. Locate the image due to refraction in air.

A slab of a material of refractive index 2 shown in fig. has a curved surface APB of radius of curvature 10 cm and a plane surface CD. On the left of APB is air and on the right CD is water with refractive indices as given in the figure. An object O is placed at a distance of 15 cm from the pole P as shown. The distance of the final image of O from P, as viewed from the left is......

The figure ,shows a transparent sphere of radius R and refractive index mu .An object O is placed at a distance x from the pole of the first surface so that a real image is formed at the pole of the exactly opposite surface. if an object is Placed at a distance R from the pole of first surface ,then the real image is formed at a distance R from thepole of the second surface.The refractive index mu of the spher is given by

(i) Device the mathematical n between refractive indices n_(1) and n_(2) of two radii and radius of curvature R for refraction at a convex shperical surface. Consider the object to be a point since lying on the principal axis in rarer medium of refractive index n_(1) and a real image formed in the denser medium of refractive index n_(2) . Hence, derive lens marker's formula. (ii) Light from a point source in air falls on a convex spherical glass surface of refractive index 1.5 and radius of curvature 20cm . The distance of light source from the glass surface is 100cm . At what position is the image formed ?

The figure ,shows a transparent sphere of radius R and refractive index mu .An object O is placed at a distance x from the pole of the first surface so that a real image is formed at the pole of the exactly opposite surface. If x=2R ,then the value of mu is

The figure ,shows a transparent sphere of radius R and refractive index mu .An object O is placed at a distance x from the pole of the first surface so that a real image is formed at the pole of the exactly opposite surface. If x=oo ,then the value of mu is

A transparent sphere of radius R and refractie index mu is kept in air. At what distance from the surface of the sphere shold a point object be placed so as to form a rea image at the same distance from the sphere?

There is a sphere of radius R and refractive index mu . At what distance from the surface of sphere should an object be placed so that real image is formed at the same distance from the sphere ?