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The intensity of the light coming from one of the slits in a Young's double slit experiment is double the intensity from the other slit. Find the ratio of the maximum intensity to the minimum intensity in the interference fringe pattern observed.

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The intensity of the light originating from the first-slit is double the intensity from the second slit. The amplitudes of the two interfering waves are-in the ratio `sqrt(2) : 1`, say `sqrt(2)` A and A.
At the point of constructive interference, the.resultant amplitude becomes `(sqrt(2)+1)A` At the points of destructive interference, this amplitude is `(sqrt(2)-1)A` The ratio of the resultant intensities at the maxima to that at the minima is
`((sqrt(2)+1)^(2)A^(2))/((sqrt(2)-1)^(2)A^(2)) =34`
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