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An object of height 0.5 cm is placed lat...

An object of height 0.5 cm is placed laterally in the medium of refractive index m = 1.5 at a distance 100 cm away form the pole. The radius of curvature of the surface is 20 cm. The height of the image formed after refraction is

A

0.8 cm

B

1 cm

C

0.25 cm

D

1.5 cm

Text Solution

Verified by Experts

The correct Answer is:
A
`n_(2)/v-n_(1)/u=(n_(2)-n_(1))/rimplies1.6/v-1.5/u=(1.6-.5)/20=1/200`
`impliesv=-160 cm`
Image height =`v/uxx` object height =`160/100xx0.5=0.8` Hence (A) is correct.
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