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In Young's double-slit experiment, let A...

In Young's double-slit experiment, let A and B be the two slit. A thin film of thickness t and refractive index `mu` is placed in front of A. Let `beta = ` fringe width. Then the central maxima will shift

A

towards A

B

towards B

C

by t`(mu-1) beta/lambda`

D

by`mut beta/lambda`

Text Solution

Verified by Experts

The correct Answer is:
A and C
Let d = distance between the slits, `lambda` = wavelength of light,
D = distance from the slits to the screen
For a point P on the screen at a distance x from the centre of the screen. Path difference = A = x(d/D)
Path difference introduced due to film = t`(mu - 1)`.
For central maximum at P
x`d/D=t(mu-1)` or `x=t(mu-1)D/d`
now, `beta=lambda D/d " or" D/d =beta/lambda`
`:. x=t(mu-1)beta/lambda` towardsA
hence(A)and(C)
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