`xdy-ydx=xy^2dx`

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What is the solution of the differential equation xdy- ydx = xy^(2) dx ?

Solve the initial value problem: (xdy+ydx)=xy dx ,y(1)=1.

The general solution of the differential equation xdy - ydx = y^(2)dx is

xdy-ydx = yes

Solve : xdy/dx+y=xy^2

Solve (i) xdx +ydy + (xdy - ydx)/(x^(2) + y^(2)) = 0 (ii) y(1+xy) dx - xdy = 0

Solve xdy + ydx - (a^(2)(xdy-ydx))/(x^(2) + y^(2))