The time `t` of a complete oscillation of a simple pendulum of length `l` is given by the equation `T=2pisqrt(1/g)` where `g` is constant. What is the percentage error in `T` when `l` is increased by 1%?

The time t of a complete oscillation of a simple pendulum of length l is given by the equation T=2 pi sqrt((1)/(g)) where g is constant.What is the percentage error in T when l is increased by 1%?

The time T, taken for a complete oscillation of a single pendulam with length l, is given by the equation T= 2pi sqrt(l/g) , where g is a constant. Find the approximate percentage error in the calculated value of T corresponding to an error of 2 percent in the value of l.

The time t of a complete oscillation of a simple pendulum of length l is given by t2pisqrt(l/g) where g is gravitational constant. Find the approximate percentage of error in t when the percentage of error in l is 1%.

The time ‘t' of a complete oscillation of a simple pendulum of length 1 is given by t=2pisqrt((l)/(g)) where gis gravitational constant. Find the approximate percentage of error in t when the percentage of error in lis 1%

The period of oscillation T of a simple pendulum of length l is connected by the relation T = 2pi sqrt((i)/(g)) , where g is a constant. Find approximately the percentage error in the computed value of T correspounding to an error of 1% in the value of l.

The time T of of oscillation of a simple pendulum of length l is given by T=2pisqrt(l/g) . Find the percentage error in T, corresponding to an error of 2% in the value of l.

The time period T of oscillation of a simple pendulum of length l is given by T=2pi. sqrt((l)/(g)) . Find the percentage error in T corresponding to 2% in the value of l.