Prove that mapping `f:I -> I`, where `I` is the set of integers and `f(x) = 5x, x in I` is one-one and into.

Let I be the set of integer and f : I rarr I be defined as f(x) = x^(2), x in I , the function is

Let I be the set of integer and f : I rarr I be defined as f(x) = x^(2), x in I , the function is

Let I be the set of integer and f : I rarr I be defined as f(x) = x^(2), x in I , the function is

Let I be the set of integer and f : I rarr I be defined as f(x) = x^(2), x in I , the function is

Let I be the set of integer and f : I rarr I be defined as f(x) = x^(2), x in I , the function is

If R is the set of real numbers prove that a function f: R -> R,f(x)=e^x , x in R is one to one mapping.

If R is the set of real numbers prove that a function f:R rarr R,f(x)=e^(x),x in R is one to one mapping.

Which of the following is not an equivalence relation on I,the set of integers x,y in I?

1 (a) answer any one question :(i) suppose IR be the set of all real no. and the mapping f:IR rarr IR is defined by f(x) = 2x^2-5x+6 . find the value of f^-1(3)