A copper electrical kettle weighing 1 kg contians 0.5 kg of water at `20@C`. It takes 10 minutes to raise the temperature to `100^@C`. If the electric energy is supplied at 220V, calculate the strength of the current,assuming that 20% heat is washed. Specific heat of copper is 0.1.

A copper electric kettle weighing 1000 g contains 900g of water at 20^(@)C it takes 12 minutes to raise the temperature to 100^(@)C . If electric energy is supplied at 210V, calculate the strength of the current, assuming that 10% heat is wasted. Specific heat of copper is 0.1.

A copper electric kettle weighing 1000 g contains 900g of water at 20^(@)C it takes 12 minutes to raise the temperature to 100^(@)C . If electric energy is supplied at 210V, calculate the strength of the current, assuming that 10% heat is wasted. Specific heat of copper is 0.1.

A copper kettle weighing 1000g holds 1900g of water at 19^(@)C. it takes 12 minutes to raise the temperatureto 100^(@)C . If energy is supplied is supplied at 210V, calculate the strength of current assuming that 10% of heat is wasted. Secific heat of copper =0.1"cal" g^(-1)C^(-1) .

A vessel made of copper weighs 1 kg and it contains 1 kg of water at 10^(@)C . How much coal will be required to raise the temperature of this water to 100^(@)C ? On burning 1 kg of coal, 10^(4) cal of heat can be produced and 40% of this heat is lost. Specific heat of copper ="0.09 cal.g"^(-1).^(@)C^(-1) .

50 gm of copper is heated to increase its temperature by 10^(@)C. If the same quantity of heat is given to 10 gm of water, the rise in its temperature is (Specific heat of copper =420 Joule-kg^(-1)@C^(-1)

50 g of copper is heated to increase its temperature by 10^@C . If the same quantity of heat is given to 10g of water, the rise in its temperature is (specific heat of copper =420J//kg^(@)//C )

50 g of copper is heated to increase its temperature by 10^@C . If the same quantity of heat is given to 10g of water, the rise in its temperature is (specific heat of copper =420J//kg^(@)//C )

75 gm of copper is heated to increase its temperature by 10^@ C . If the same quantity of heat is given to 'm' gm of water, to have same rise in temperature is (specific heat of copper = 420 J//Kg-^@ C ).

1300 J of heat energy is supplied to raise the temperature of 0.5 kg of lead from 20^@ C to 40^@ C. Calculate the specific heat capacity of lead.