When `22.4 L` of `H_(2)(g)` is mixed with 11.2 of `Cl_(2)(g)`, each at STP, the moles of HCl(g) formed is equal to

When 22.4 L of H_(2)(g) is mixed with 11.2 L of Cl_(2)(g) , each at STP, the moles of HCl(g) formed is equal to

When 22.4 litres of H_(2)(g) is mixed with 11.2 litres of Cl_(2)(g) , each at STP, the moles of HCl (g) formed is equal to-

When 22.4 litres of H_(2(g)) is mixed with 11.2 litres of Cl_(2(g)) each at STP, the no. of moles of HCI_((g)) formed is equal to