If `[(1,2,3),(3,1,2),(2,3,1)][(x),(y),(z)]=[(4,-2),(0,-6),(-1,2)][(2),(1)]`, then `(x,y,z)=`

If [{:(1,1,1),(1,-2,-2),(1,3,1):}][{:(x),(y),(z):}]=[{:(0),(3),(4):}] , then [{:(x),(y),(z):}] is equal to

If [{:(1,1,1),(1,-2,-2),(1,3,1):}][{:(x),(y),(z):}]=[{:(0),(3),(4):}] , then [{:(x),(y),(z):}] is equal to

If X= [(2,3,0),(1,-1,5)] ,Y= [(-1,-2,3),(-1,0,2)] ,Z= [(0,4,-1),(5,6,-5)] find 3X+4Y-Z

If ((x+3,2y+x),(z-1,4a-z))=[(0,-7),(3,2a)] then x+y+z+a=

Use the product [(1,-1,2),(0,2,-3),(3,-2,4)][(-2,-0,1),(9,2,-3),(6,1,-2)] to solve the system of equations x - y + 2z = 1 2y - 3z = 1 3x - 2y + 4z = 2

Use product : {:[(1,-1,2),(0,2,-3),(3,-2,4)][(-2,0,1),(9,2,-3),(6,1,-2)] to solve the system of equations: x-y+2z=1,2y-3z=1,3x-2y+4z=2

Use product [{:(1,-1,2),(0,2,-3),(3,-2,4):}][{:(-2,0,1),(9,2,-3),(6,1,-2):}] to solve the equations : x-3z=9 , -x+2y-2z=4 , 2x-3y+4z=-3

If [[1, 1, 1], [1, -2, -2], [1, 3, 1]][[x], [y], [z]]=[[0], [3], [4]] , then [[x], [y], [z]]=