A real valued function f(x) satisfies the functional equation `f(x-y) = f(x) f(y) - f(a-x) f(a+y)`, where a is a given constant and f(0), f(2a-x) =

A real valued function f(x) satisfies the functional equation f(x-y) = f(x) f(y) - f(a-x) f(a+y) , where a is a given constant and f(0)=1 , f(2a-x) =?

A real valued function f(x) satisfies the functional equation f(x-y) = f(x) f(y) - f(a-x) f(a+y) , where a is a given constant and f(0)=1 , f(2a-x) =?

A real valued function f (x) satisfies the functional equation f (x-y)= f(x) f(y) - f(a-x) f(a +y) where a is a given constant and f (0) =1, f(2a -x) is equal to

A real valued function f(x) satisfies the functional equation f(x-y) = f(x)f(y)-f(a - x)f(a + y) where a is a given constant and f(0)=1, f(2a-x) is equal to:

A real valued function f (x) satisfies the functional equation f (x-y)=f(x)f(y)- f(a-x) f(a+y) where 'a' is a given constant and f (0) =1, f(2a-x) is equal to :

A ral valued functin f (x) satisfies the functional equation f (x-y)=f(x)f(y)- f(a-x) f(a+y) where 'a' is a given constant and f (0) =1, f(2a-x) is equal to :

A real valued function f(x) satisfies the functional equation : f(x-y)=f(x)f(y)-f(a-x)f(a+y) , where a is given constant and f(0)=1.f(2a-x) is equal to :

A real valued function f (x) satisfied the functional relation f (x-y)=f (x)f(y) -f(a-x) f(a+y) where a is a given constant and f(0) =1. Then f (2a-x) is equal to-

A real valued function f(x) stisfies the functional relation f(x-y)=f(x)f(y)-f(a-x)f(a+y) where a is a given constant and f(0)=1. Then, f(2a-x) is equal to -