If `(67^(67)+67)` is divided by 68, the remainder is 1 (b) 63 (c) 66 (d) 67

What is the remainder when ((67^(67))+67) is divided by 68.(A)1(B)63(C)66(D)67

Find the remainder when N is divided by 168 .33 (b) 67(c)129 (d) 153

A number divided by 68 gives the quotient 269 and remainder zero. If the same number is divided by 67, the remainder is :

A number divided by 68 gives the quotient 269 and remainder zero. If the same number is divided by 67, the remainder is:

(-35)+(-32) is equal to 67 (b) -67 (c) -3 (d) 3

(i^(95)+i^(67)) =

The number (2^(48)-1) is exactly divisible by two numbers between 60 and 70.The numbers are 63 and 65 (b) 63 and 67 (c) 61 and 65 (d) 65 and 67

The whole number n satisfying n+35=101 is (a)65 (b) 67 (c) 64 (d) 66